AUGUSTINE - Math tutor - Columbus
1st lesson free
AUGUSTINE - Math tutor - Columbus

AUGUSTINE's email address and phone number have been validated.

AUGUSTINE

  • Rate $42
  • Response 24h
  • Students

    Number of students AUGUSTINE has accompanied since arriving at Superprof

    8

    Number of students AUGUSTINE has accompanied since arriving at Superprof

AUGUSTINE - Math tutor - Columbus
  • 5 (2 reviews)

$42/h

1st lesson free

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1st lesson free

1st lesson free

  • Math
  • Algebra
  • Geometry
  • Algorithms
  • Exam Prep- Sciences BAC

New York's "best math teacher" with over 23 years experience teaching & tutoring with great success! he breaks every material down to your level so you can understand and master in a short time! NY Ce

  • Math
  • Algebra
  • Geometry
  • Algorithms
  • Exam Prep- Sciences BAC

Lesson location

Recommended

AUGUSTINE is a respected tutor in our community. They are highly recommended for their commitment and the quality of their lessons. An excellent choice to progress with confidence.

About AUGUSTINE

"No one teaches like Mr. Augustine!" "Ohh why didn't they teach me this way?" "Mr. you make it sooo easy!" These and others are constant refrains in my tutoring and teaching sessions. It is not for nothing that hundreds and thousands of students have passed through my hands successfully over these twenty-something years in America, and most have become big people now. I make education very easy, and I take the mystery and myth out of Mathematics. What is more, I enjoy doing that - I enjoy solving the learning problem you have by explaining the concepts and making it so easy for you. It's time for you to try and be on the receiving end of the educational wonders through "TUTORING WITH MR. AUGUSTINE!" It was no surprise that in 2007 the Education chancellor of New York publicly praised me as New York's most outstanding Math Teacher for all the record successes I was making in the students! Since I enjoy doing it, I'm still at it, and probably better at it even now! Will you be the next success story?

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About the lesson

  • Elementary School
  • Middle School
  • High School
  • +9

    • levels :

    Elementary School

    Middle School

    High School

    Première

    Terminale

    College

    University

    Adult Education

    Masters/ Graduate School

    Doctorate

    MBA

    Early childhood education

  • English

All languages in which the lesson is available :

English

They say I can teach Math to even a goat to understand because I explain the material well with step by step methods and examples! No one fails in my class! Success is guaranteed!
I teach/tutor from College levels, High School levels, Adult, GED, Standardized Tests like GRE, GMAT, SAT, ACT, HSPT, SHSAT, HESI, TEAS, Nursing Prep, as well as junior levels like from grades 3-8.
Also help with Term Papers, Proofreading, College level Essays, English Language, Literature, Philosophy, Sociology, Biblical Studies, Psychology, and MATHEMATICS for all levels - Arithmetic, Pre-Algebra, Algebra 1, Geometry, Algebra 2, Trigonometry, Pre-Calculus, Statistics, Calculus 1,2,3,4; Differential Equations, Discrete Mathematics, Linear Algebra, AP courses, CLEP courses, etc.
TYPICAL LESSON PLAN :
Topic: How do we solve quadratic Equations by Factoring?
I. INTRODUCTION:
1- To solve a quadratic equation means to find the x-values, also called the roots, or the solutions. These are the points where the graph crosses the x-axes.
2- We can solve the quadratic equation by any of the following methods:
a- By factoring
b- By the quadratic formula
c- By completing the square
d- By graphing.
II. HOW DO WE SOLVE THE QUADRATIC EXPRESSION BY FACTORING?
Step 1: Factor the expression
Step 2: Equate the factors to zero and solve
Example: What are the solutions of the expression x^2 -7x + 12 ?
SOLUTION:
Step 1: x^2 - 7x +12 : Factors of x^2 are x and x (x ) (x )
Factors of 12 are 6 &2; 12 & 1; and 4 &3. Since the coefficient of the x^2, which is the "a" term,= 1, we need to pick those two factors of 12 which can add or subtract to give us the middle number. In this case, the middle number is -7. Among the three choices above, only 4&3 can give us 7, that is, -4 +-3 = -7. When we multiply -4 by -3, we will also get the "c" term, 12. So this works for us. So our factors should be:
( x-4 ) (x-3)
Step 2: (x-4)(x-3) = 0 means either (x-4) =0 or (x-3) =0
If x-4 = 0, then adding 4 to both sides, x = 4
If x -3 = 0, then adding 3 to both sides, x = 3
CHECK: If x =4, 4^2 - 7(4) + 12 = 0 If x =3, 3^2 -7(3) +12 = 0
16 -28 +12 = 0 9 -21 + 12 = 0
28-28 = 0 21-21 =0
0=0 0=0
They both work!

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Rates

Rate

  • $42

Pack rates

  • 5 h: $197
  • 10 h: $351

free lessons

This first lesson offered with AUGUSTINE will allow you to get to know each other and clearly specify your needs for your next lessons.

  • 1hrs

online

  • $42/h

Details

After 4 hours in a week you get extra hour for free if used within the same week.
A package of 4 hours a week comes with more discounts - ask about it. A second, third, and fourth student from the same house all bring more discounts. Extremely affordable and highly effective - try it and see.

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levels

Elementary School

Middle School

High School

Première

Terminale

College

University

Adult Education

Masters/ Graduate School

Doctorate

MBA

Early childhood education

All languages in which the lesson is available

English

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free lessons

This first lesson offered with AUGUSTINE will allow you to get to know each other and clearly specify your needs for your next lessons.

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